Object is thrown by 50 meter per second at an angle 30 degrees above horizontally find the time required to hit the ground
"v_y=v_0\\sin30\u00b0-gt\\to 0=v_0\\sin30\u00b0-gt"
"t=\\frac{v_0\\sin30\u00b0}{g}"
"t_{total}=2t=2\\cdot\\frac{v_0\\sin30\u00b0}{g}=2\\cdot\\frac{50\\sin30\u00b0}{9.8}=5.1\\ (s)" . Answer
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