Object is thrown by 50 meter per second at an angle 30 degrees above horizontally find the time required to hit the ground
vy=v0sin30°−gt→0=v0sin30°−gtv_y=v_0\sin30°-gt\to 0=v_0\sin30°-gtvy=v0sin30°−gt→0=v0sin30°−gt
t=v0sin30°gt=\frac{v_0\sin30°}{g}t=gv0sin30°
ttotal=2t=2⋅v0sin30°g=2⋅50sin30°9.8=5.1 (s)t_{total}=2t=2\cdot\frac{v_0\sin30°}{g}=2\cdot\frac{50\sin30°}{9.8}=5.1\ (s)ttotal=2t=2⋅gv0sin30°=2⋅9.850sin30°=5.1 (s) . Answer
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