Question #200167

a 60 kg boy climbs a 12 m rope in 18 seconds. What is his power output


1
Expert's answer
2021-05-30T13:31:18-0400
P=FvP=mghtP=(60)(9.8)(12)18=392 WP=Fv\\P=\frac{mgh}{t}\\P=\frac{(60)(9.8)(12)}{18}=392\ W


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