Water flows over hulugan falls, which is 70m high, at an average rate of 2.3 x 10^5 kg/s. If half the potential energy of this water were converted into electric energy, how much power would be produced by these falls
"P_e=W\/t=\\frac{1}{2}mgh\/t=\\frac{1}{2}\\cdot m_0t\\cdot gh\/t=\\frac{1}{2}\\cdot m_0\\cdot gh="
"=0.5\\cdot2.3\\cdot10^5\\cdot9.8\\cdot70=78.89\\cdot10^6 \\ (W)=78.89\\ (MW)"
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