a) Let's first find the flow speed in a 4 cm diameter pipe 6m above from the Law of Continuity:
A1v1=A2v2,v2=A2A1v1=πr22πr12v1,v2=π(0.04 m)2π(0.1 m)2⋅0.6 sm=3.75 sm.b) We can find the pressure in a 4 cm diameter pipe 6m above from Bernoulli’s equation:
P1+ρgh1+21ρv12=P2+ρgh2+21ρv22,P2=P1+ρg(h1−h2)+21ρ(v12−v22),P2=3.039⋅105 Pa+1000 m3kg⋅9.8 s2m⋅(0 m−6 m)+21⋅1000 m3kg⋅((0.6 sm)2−(3.75 sm)2)=2.4⋅105 Pa.
Comments
This was very helpful thanks a lot