Question

a ball is projected vertically upwards from a height of 2m above the ground level.its initial speed is 8m/s.find the maximum height reached by the ball above the ground

Answer 1

The maximum height is the 2 m plus the height reached by the ball:

$$H_\text{max}=h+h_\text{up},\\\space\\ H_\text{max}=h+\frac{v^2}{2g},\\\space\\ H_\text{max}=2+\frac{8^2}{2·9.8}=5.27\text{ m}$$