Answer to Question #199356 in Physics for Lush

Question #199356

negative charge of -5.0x10^-4 C exerts an attractive force of 12 N on a second charge that is 0.040 m away. what is the magnitude of the second charge?

Expert's answer

"F=k\\frac{q_1q_2}{r^2}\\\\12=9\\cdot10^9\\frac{5\\cdot10^{-4}q_2}{0.04^2}\\\\q_2=4.3\\cdot10^{-9}\\ C"

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