A 100-N weight is suspended at the middle of a rope forming a letter “Y” with the angle between the ropes being 150°. Find the tensions in the rope.
W=2T⋅cos75°→T=W2cos75°=1002⋅cos75°=193.2 (N)W=2T\cdot\cos75°\to T=\frac{W}{2\cos75°}=\frac{100}{2\cdot\cos75°}=193.2\ (N)W=2T⋅cos75°→T=2cos75°W=2⋅cos75°100=193.2 (N) . Answer
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments