Question #199237

A 100-N weight is suspended at the middle of a rope forming a letter “Y” with the angle between the ropes being 150°. Find the tensions in the rope.


1
Expert's answer
2021-05-28T07:18:20-0400

W=2Tcos75°T=W2cos75°=1002cos75°=193.2 (N)W=2T\cdot\cos75°\to T=\frac{W}{2\cos75°}=\frac{100}{2\cdot\cos75°}=193.2\ (N) . Answer

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS