The coil is rotated through an angle of 90° in 2.0 second. Calculate the magnitude of the average e.m.f. induced in the coil while it is being rotated.
E=∣dΦdt∣=ΔΦΔt=12ΔΦE=|\frac{d\Phi}{dt}|=\frac{\Delta\Phi}{\Delta t}=\frac{1}{2}\Delta\PhiE=∣dtdΦ∣=ΔtΔΦ=21ΔΦ
Assume that ΔΦ=8 (Wb)\Delta\Phi=8\ (Wb)ΔΦ=8 (Wb). Then
E=12⋅8=4 (V)E=\frac{1}{2}\cdot8=4\ (V)E=21⋅8=4 (V) . Answer
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