Question

A uniform bar 3.00 m long is held by ropes at the ends making angle 60.0 and 30.0, respectively, with the horizontal. A weight of 200 N is hung 0.500 m from the left end where the 60.0 rope is attached. Find the tension in the ropes (T1 & T2) and the weight (W) of the bar. (Hint: Formulate three equations for the three unknowns, 2 equations for the 1st condition and 1 equation for the 2nd condition.)

Answer 1

$$W+200=T_1\sin{60}+T_2\sin{30}\\T_1\cos{60}=T_2\cos{30}\\ 200(1)=T_1(1.5)\sin{60}-T_2(1.5)\sin{30}$$

$$T_1=231\ N\\T_2=133\ N\\ W=67\ N$$