A car travels one-third of the path with the speed of 40 km/h, one-fourth of the path with a speed of 30 km/h and the remaining part of the path with a speed of 50 Km/h. What is the avarege speed of the car for the whole trip in km/h
vavr=s/3+s/4+5s/12s/(3⋅40)+s/(4⋅30)+5s/(12⋅50)=v_{avr}=\frac{s/3+s/4+5s/12}{s/(3\cdot40)+s/(4\cdot30)+5s/(12\cdot50)}=vavr=s/(3⋅40)+s/(4⋅30)+5s/(12⋅50)s/3+s/4+5s/12=
=11/(3⋅40)+1/(4⋅30)+5/(12⋅50)=40 (km/h)=\frac{1}{1/(3\cdot40)+1/(4\cdot30)+5/(12\cdot50)}=40\ (km/h)=1/(3⋅40)+1/(4⋅30)+5/(12⋅50)1=40 (km/h) . Answer
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