Gauge no. 36 copper wire has a diameter of 0.058m. Find the length of no. 36 copper wire which will give a resistance of 0.0005 ohms
R=ρl/AR=\rho l/AR=ρl/A
A=πd2/4=3.14⋅0.0582/4=0.00264 (m2)A=\pi d^2/4=3.14\cdot0.058^2/4=0.00264\ (m^2)A=πd2/4=3.14⋅0.0582/4=0.00264 (m2)
l=R⋅A/ρ=0.0005⋅0.00264/1.75⋅10−8=75.45 (m)l=R\cdot A/\rho=0.0005\cdot 0.00264/1.75\cdot10^{-8}=75.45\ (m)l=R⋅A/ρ=0.0005⋅0.00264/1.75⋅10−8=75.45 (m) . Answer
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