A He-Ne laser having an emergent beam diameter of 1 cm is flashed on to the moon surface. If the distance between the earth and moon is 3,84,403 km, what would be the diameter of the laser beam spot on the moon?
θ=1.22λ/d=1.22⋅632.8⋅10−9/0.01=0.0000772 (rad)\theta=1.22\lambda/d=1.22\cdot632.8\cdot10^{-9}/0.01=0.0000772\ (rad)θ=1.22λ/d=1.22⋅632.8⋅10−9/0.01=0.0000772 (rad)
D=2⋅l⋅tanθ=2⋅384403000⋅tan0.0000772=59353 (m)D=2\cdot l\cdot\tan\theta=2\cdot384403000\cdot\tan0.0000772=59353\ (m)D=2⋅l⋅tanθ=2⋅384403000⋅tan0.0000772=59353 (m) . Answer
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