A mass of 55 g hangs from a vertical spring how can you find the spring constant, is the answer a) 319n/m, b) 9.3n/m c) -0.00094 n/m d)320n/m
mg=kΔx→k=mg/Δxmg=k\Delta x\to k=mg/\Delta xmg=kΔx→k=mg/Δx
To determine the spring constant, we need to know its elongation.
Assume that Δx=0.058 (m)\Delta x=0.058\ (m)Δx=0.058 (m) . So, we have
k=mg/Δx=0.055⋅9.8/0.058≈9.3 (N/m)k=mg/\Delta x=0.055\cdot9.8/0.058\approx9.3\ (N/m)k=mg/Δx=0.055⋅9.8/0.058≈9.3 (N/m)
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