Question

Calculate the specific heat of a substance if 420 calories is needed to raise the temperature of

this 75 grams substance from 15 ᵒC to 50 ᵒC.

Answer 1

The heat required to change the temperature:

$$Q=cm\Delta t,\\\space\\ c=\frac{Q}{m\Delta t}=\frac{420}{75·(50-15)}=0.16\text{ cal/(g°C)}.$$