Question #195885

A juggler tosses three balls alternately vertically upward. Each ball has an initial velocity of 5m/s. How high does each ball rise? How long does each ball remain in the air? Show your solution


1
Expert's answer
2021-05-20T10:08:29-0400

h=v02/(2g)=52/(29.8)=1.276 (m)h=v_0^2/(2g)=5^2/(2\cdot9.8)=1.276\ (m) . Answer


t=2t0t=2t_0


v=v0gtt=(v0v)/g=(50)/9.8=0.51 (s)v=v_0-gt\to t=(v_0-v)/g=(5-0)/9.8=0.51\ (s)


t=20.51=1.02 (s)t=2\cdot0.51=1.02\ (s) . Answer

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