Question

A set of charged plates is separated by 2.22*10^-4m. When 5.24*10^-9 C of charge is placed on the plates, it creates a potential difference of 240 V. What is the are of the plates?

Answer 1

With the provided information, we can find the capacitance of the system:

$$C=\frac QV.$$

On the other hand, the capacitance can be expressed as

$$C=\frac{\epsilon_0A}{d},\\\space\\ A=\frac{Cd}{\epsilon_0}=\frac{Qd}{V\epsilon_0}=5.47\text{ cm}^2.$$