Answer to Question #194876 in Physics for Deborah

Question #194876

A catapult used to hold a stone of mass 500g is extended by 20cm with an applied force F. If the stone leaves with a velocity of 40ms^-1 the value of F is

Expert's answer

According to Newton's second law,

"F=ma,\\\\\\space\\\\\na=\\frac{v^2}{2d},\\\\\\space\\\\\nF=\\frac{v^2m}{2d}=2000\\text{ N}."

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