Question #194799

A man drives horizontally off the cliff at 20 m/s. He lands 40m from the base of the cliff. How high is the cliff?


1
Expert's answer
2021-05-18T11:09:52-0400

t=40/20=2 (s)t=40/20=2\ (s)


h=gt2/2→9.8⋅22/2=19.6 (m)h=gt^2/2\to 9.8\cdot2^2/2=19.6\ (m) . Answer

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