Question #194749

An elevator motor in a high-rise building can do 3500 kJ of work in 5 min. Find the power developed by

the motor.


1
Expert's answer
2021-05-20T18:24:28-0400
P=Wt=3.5⋅106 J5⋅60 s=11667 W=11.6 kW.P=\dfrac{W}{t}=\dfrac{3.5\cdot10^6\ J}{5\cdot60\ s}=11667\ W=11.6\ kW.

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