Question #194745

A heat engine does 23 kJ of work during 1800 s. Find the power supplied by the engine.


1
Expert's answer
2021-05-18T11:10:15-0400
P=Wt=23103 J1800 s=12.8 W.P=\dfrac{W}{t}=\dfrac{23\cdot10^3\ J}{1800\ s}=12.8\ W.

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