Question

A 12.0 kg object is pushed with a horizontal force of 6.0 N easy across a horizontal table. If the force of friction between the two surfaces is 2.0 N, what is the acceleration of the object?

Answer 1

$$F_{net}=ma,$$ $$F_h-F_{fr}=ma,$$ $$a=\dfrac{F_h-F_{fr}}{m}=\dfrac{6\ N-2\ N}{12\ kg}=0.33\ \dfrac{m}{s^2}.$$