Question #194460

In a dielectric material with ∈_r=3.6 , D= 285 nC/m^2. Find the magnitudes of E, P, and electric susceptibility


1
Expert's answer
2021-05-17T13:31:59-0400

As we know,


D=ϵ0ϵrE, E=Dϵ0ϵr=8941 V/m.D=\epsilon_0\epsilon_rE,\\\space\\ E=\frac{D}{\epsilon_0\epsilon_r}=8941\text{ V/m}.

On the other hand, we know that


D=ϵ0E+P,P=Dϵ0E=205.8109 C/m2.D=\epsilon_0E+P,\\ P=D-\epsilon_0E=205.8·10^{-9}\text{ C/m}^2.

Find electric susceptibility:


P=ϵ0χeE, χe=Pϵ0E=2.6.P=\epsilon_0\chi_eE,\\\space\\ \chi_e=\frac{P}{\epsilon_0E}=2.6.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS