A 500 grams of copper at 300 0 C and 350 grams lead at 550 0 C are put in 1200grams of aluminium container filled with one litre of water at 20 0 C. Solve for the final temperature reading.
c1m1(300−t)+c2m2(550−t)=c3m3(t−20)+c4m4(t−20)c_1m_1(300-t)+c_2m_2(550-t)=c_3m_3(t-20)+c_4m_4(t-20)c1m1(300−t)+c2m2(550−t)=c3m3(t−20)+c4m4(t−20)
385⋅0.5⋅(300−t)+130⋅0.35⋅(550−t)=920⋅1.2⋅(t−20)+4218⋅1⋅(t−20)→385\cdot 0.5\cdot(300-t)+130\cdot 0.35\cdot(550-t)=920\cdot 1.2\cdot(t-20)+4218\cdot 1\cdot(t-20)\to385⋅0.5⋅(300−t)+130⋅0.35⋅(550−t)=920⋅1.2⋅(t−20)+4218⋅1⋅(t−20)→
t=34 (°C)t=34\ (°C)t=34 (°C) . Answer
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