Question

a bathtub contains 70 kg of water at 26C. Ten kg of water at 90C is poured in. what is the final temperature of the mixture.

Answer 1

$cm_1(t-26)=cm_2(90-t)$

$4218\cdot 70\cdot(t-26)=4218\cdot 10\cdot(90-t)\to$

$t=34\ (°C)$ . Answer