a bathtub contains 70 kg of water at 26C. Ten kg of water at 90C is poured in. what is the final temperature of the mixture.
"cm_1(t-26)=cm_2(90-t)"
"4218\\cdot 70\\cdot(t-26)=4218\\cdot 10\\cdot(90-t)\\to"
"t=34\\ (\u00b0C)" . Answer
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