Question #193543

A 2.00 kg mass is placed on the top of a hill 10.0 m high. Assume no energy is being lost through heat or friction. If the spring compresses 0.500 m when the ball comes to a stop, what is the spring constant?


1
Expert's answer
2021-05-14T18:22:33-0400

mgh=kx2/2k=2mgh/x2=229.8110/0.52=1570 (N/m)mgh=kx^2/2\to k=2mgh/x^2=2\cdot2\cdot9.81\cdot 10/0.5^2=1570\ (N/m) . Answer






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