a stone of mass 20 g is released from a catapult whose rubber has been stretched through 4cm. if the force constant of the rubber is 200N/m calculate the velocity with which the phone leaves the catapult
"kx^2\/2=mv^2\/2\\to v=\\sqrt{kx^2\/m}=\\sqrt{200\\cdot 0.04^2\/0.02}=4\\ (m\/s)" . Answer
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