Two particles are each given a charge of 5 × 10-5 C. What is the force between the charged particles if the distance between them is 2 meters?
F=kq1q2x2=9⋅109⋅5⋅10−5⋅5⋅10−522=5.625 (N)F=k\frac{q_1q_2}{x^2}=9\cdot10^9\cdot\frac{5\cdot10^{-5}\cdot5\cdot10^{-5}}{2^2}=5.625\ (N)F=kx2q1q2=9⋅109⋅225⋅10−5⋅5⋅10−5=5.625 (N) . Answer
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