if a hydroelectric station is 93% efficient. What mass of water must pass through the station each 1.00s to produce 855kW of electricity from a 34.6 meter drop?
"W=mgh\\to0.93mgh=Pt\\to m=\\frac{Pt}{0.93gh}="
"=\\frac{855000\\cdot1}{0.93\\cdot9.81\\cdot34.6}=2709\\ (m^3)"
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