Question #192122

Given that the charge of 6.25 x 1018 electrons has a charge of 1C, calculate the charge of 1 electron


1
Expert's answer
2021-05-11T16:35:19-0400
q=QNq=16.25⋅1018=1.6⋅10−19Cq=\frac{Q}{N}\\q=\frac{1}{6.25\cdot10^{18}}=1.6\cdot10^{-19}C


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