A cart is initially travelling across a flat surface with a velocity of 1.6 m/s. A net force of 87 N is
exerted on the cart over a distance of 15.4 m for 4.1 s. What is the mass of the cart?
s=v0t+at2/2→a=2(s−v0t)t2=2(15.4−1.6⋅4.1)4.12=1.052 (m/s2)s=v_0t+at^2/2\to a=\frac{2(s-v_0t)}{t^2}=\frac{2(15.4-1.6\cdot 4.1)}{4.1^2}=1.052\ (m/s^2)s=v0t+at2/2→a=t22(s−v0t)=4.122(15.4−1.6⋅4.1)=1.052 (m/s2)
F=ma→m=F/a=87/1.052=82.7 (kg)F=ma\to m=F/a=87/1.052=82.7\ (kg)F=ma→m=F/a=87/1.052=82.7 (kg) . Answer
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