Question

15. Calculate What is the pressure of an ideal gas if there are 2.2 X 102 particles in a volume of 0.026 m at a temperature of 290 K?

Answer 1

We know that

$$p=nkT=\frac NVkT,\\\space\\ p=\frac{2.2·10^2}{0.026}1.38·10^{-23}·290=3.39·10^{-17}\text{ Pa}.$$