Question #191843

A 2kg mass slides down an inclined plane of 27 degrees from top to bottom in 3 seconds. Assuming the coefficient of friction between the two surfaces is 0.48, calculate all the force components including friction and determine the length of the ramp.


Present your answer with a vector diagram.

Present each component of your answer.


1
Expert's answer
2021-05-12T08:38:10-0400


Find the x-component of mg:


(mg)x=mgsin27°=8.90 N.(mg)_x=mg\sin27°=8.90\text{ N}.

Find the normal force N:


N=Ny=(mg)y=mgcos27°=17.5 N.N=N_y=(mg)_y=mg\cos27°=17.5\text{ N}.

Find the force of friction:


f=fx=μN=8.40 N.f=f_x=\mu N=8.40\text{ N}.

Find the acceleration:


a=Fnetm, Fnet=f(mg)x=0.50 N, a=0.25 m/s2.a=\frac{F_\text{net}}{m},\\\space\\ F_\text{net}=f-(mg)_x=-0.50\text{ N},\\\space\\ a=-0.25\text{ m/s}^2.

The length of the ramp:


L=at22=1.125 m.L=\frac{|a|t^2}{2}=1.125\text{ m}.



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