A bus starts from rest and accelerates at 1.5 m/s2 until it reaches a velocity of 9m/s. The bus continues at this velocity and then accelerates at -2 m/s2 until it comes to a stop 400m from its starting point. How much time did the bus take to cover the 400m?
"s_1=v^2\/(2a_1)=9^2\/(2\\cdot1.5)=27\\ (m)" ; "v=a_1t_1\\to t_1=v\/a_1=9\/1.5=6\\ (s)"
"s_3=v^2\/(2a_3)=9^2\/(2\\cdot2)=20.25\\ (m)" ; "v'=v-a_3t_3\\to t_3=v\/a_3=9\/2=4.5\\ (s)"
"s_2=400-27-20.25=352.75\\ (m)" ; "t_2=s_2\/v=352.75\/9=39.19\\ (s)"
"t=6+4.5+39.19=49.69\\ (s)" . Answer
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