An object is dropped from rest at a height of 300m. Find: a.) its velocity
after 2 sec. b.) the time it takes for the object to reach the ground c.) what velocity does it
hit the ground?
a) v=gt=9.81⋅2=19.62 (m/s)v=gt=9.81\cdot2=19.62\ (m/s)v=gt=9.81⋅2=19.62 (m/s)
b) s=gt2/2→t=2sg=2⋅3009.81=7.82 (s)s=gt^2/2\to t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2\cdot 300}{9.81}}=7.82\ (s)s=gt2/2→t=g2s=9.812⋅300=7.82 (s)
c) mgh=mv2/2→v=2gh=2⋅9.81⋅300=76.72 (m/s)mgh=mv^2/2\to v=\sqrt{2gh}=\sqrt{2\cdot9.81\cdot300}=76.72\ (m/s)mgh=mv2/2→v=2gh=2⋅9.81⋅300=76.72 (m/s)
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