Question #190954

A circular coil of 4 turns with a radius of 0.03m., and it is subjected to a varying magnetic field that changes uniformly from 0.4 T to 3.4 T in an interval of 27s. The axis of the solenoid makes an angle of 35° to the magnetic field. Find the induced EMF. (A = π r2)ε = - N (ΔΦ / Δt)= N (A cos!) (Bf – Bi)


1
Expert's answer
2021-05-09T15:21:02-0400

Let’s use the Faraday’s law and find the induced emf: 


E=NΔΦΔt,\Epsilon=-N\dfrac{\Delta\Phi }{\Delta t},E=NAcosθ(BfBi)Δt,\Epsilon=N\dfrac{Acos\theta(B_f-B_i)}{\Delta t},E=Nπr2cosθ(BfBi)Δt,\Epsilon=N\dfrac{\pi r^2cos\theta(B_f-B_i)}{\Delta t},E=4π(0.03 m)2cos35(3.4 T0.4 T)27 s=1.03103 V.\Epsilon=4\cdot\dfrac{\pi(0.03\ m)^2\cdot cos35^{\circ}\cdot(3.4\ T-0.4\ T)}{27\ s}=1.03\cdot10^{-3}\ V.

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