Answer to Question #190917 in Physics for Luna

Question

a truck is moving. when the truck is ahead of a car which is at rest, the truck having a speed of 50 m/s at that point accelerates at 1 m/s^2. three seconds later, the car starts and accelerates at 4m/s^2. when and where will the car overtake the truck? what are their velocities at that point?

Answer 1

$s=v_0(t_0+t)+a_1(t_0+t)^2/2=50(3+t)+(3+t)^2/2$

$s=a_2t^2/2=4t^2/2=2t^2$

$50(3+t)+(3+t)^2/2=2t^2\to t=38.041\ (s)$ . Answer

$s=2\cdot 38.041^2=2894\ (m)$ . Answer

$v_1=50+1\cdot38.041=88.041\ (m/s)$ . Answer

$v_2=4\cdot38.041=152.16 \ (m/s)$ . Answer