Question #190917

a truck is moving. when the truck is ahead of a car which is at rest, the truck having a speed of 50 m/s at that point accelerates at 1 m/s^2. three seconds later, the car starts and accelerates at 4m/s^2. when and where will the car overtake the truck? what are their velocities at that point?


1
Expert's answer
2021-05-09T13:04:02-0400

s=v0(t0+t)+a1(t0+t)2/2=50(3+t)+(3+t)2/2s=v_0(t_0+t)+a_1(t_0+t)^2/2=50(3+t)+(3+t)^2/2


s=a2t2/2=4t2/2=2t2s=a_2t^2/2=4t^2/2=2t^2


50(3+t)+(3+t)2/2=2t2t=38.041 (s)50(3+t)+(3+t)^2/2=2t^2\to t=38.041\ (s) . Answer


s=238.0412=2894 (m)s=2\cdot 38.041^2=2894\ (m) . Answer


v1=50+138.041=88.041 (m/s)v_1=50+1\cdot38.041=88.041\ (m/s) . Answer


v2=438.041=152.16 (m/s)v_2=4\cdot38.041=152.16 \ (m/s) . Answer







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