Question #190302

A 2.0 kg particle moves as a function of time as follows:

             x = 3.5 sin (1.5t+π/2)

Where, distance is measured in meters and time in seconds.

(a) What is the amplitude, frequency, angular frequency, and period of this motion?



1
Expert's answer
2021-05-07T09:44:56-0400

Amplitude A=3.5 (m)A=3.5 \ (m)


Angular frequency ω=1.5 (rad/s)\omega=1.5\ (rad/s)


Frequency f=ω2π=1.523.14=0.24 (Hz)f=\frac{\omega}{2\pi}=\frac{1.5}{2\cdot 3.14}=0.24\ (Hz)


Period T=1f=10.24=4.17 (s)T=\frac{1}{f}=\frac{1}{0.24}=4.17\ (s)


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