Question

 a 4.1 kg ball is thrown directly with an initial speed of 36.4 m/s and reaches a maximum height of 5.4 m how mich mechanical energy is lost because of air drag during the ascent 

Answer 1

$$\Delta E=0.5mv^2-mgh\\\Delta E=0.5(4.1)(36.4)^2-(4.1)(9.8)(5.4)=2500\ J$$