The wall of house, 7m wide and 6m high is made from 0.3m thick brick with kT =0.6 W/m-K. The surface
temperature on the inside of the wall is 16˚C and that on the outside is 6˚C and that on the outside is 6˚C. Find
the total heat loss per second through it.
Q=kΔTΔxAtQ=k\frac{\Delta T}{\Delta x}AtQ=kΔxΔTAt
A=7⋅6=42 (m2)A=7\cdot6=42\ (m^2)A=7⋅6=42 (m2)
t=1 (s)t=1\ (s)t=1 (s)
ΔT=16−6=10 (°C)\Delta T=16-6=10\ (°C)ΔT=16−6=10 (°C)
Δx=0.3 (m)\Delta x=0.3\ (m)Δx=0.3 (m)
k=0.6 (W/(m⋅K))k=0.6\ (W/(m\cdot K))k=0.6 (W/(m⋅K))
Q=0.6⋅100.3⋅42⋅1=840 (J)Q=0.6\cdot\frac{10}{0.3}\cdot42\cdot1=840\ (J)Q=0.6⋅0.310⋅42⋅1=840 (J) . Answer
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