Question #189792

The wall of house, 7m wide and 6m high is made from 0.3m thick brick with kT =0.6 W/m-K. The surface 

temperature on the inside of the wall is 16˚C and that on the outside is 6˚C and that on the outside is 6˚C. Find

the total heat loss per second through it.


1
Expert's answer
2021-05-06T07:41:53-0400

Q=kΔTΔxAtQ=k\frac{\Delta T}{\Delta x}At


A=76=42 (m2)A=7\cdot6=42\ (m^2)

t=1 (s)t=1\ (s)

ΔT=166=10 (°C)\Delta T=16-6=10\ (°C)

Δx=0.3 (m)\Delta x=0.3\ (m)

k=0.6 (W/(mK))k=0.6\ (W/(m\cdot K))


Q=0.6100.3421=840 (J)Q=0.6\cdot\frac{10}{0.3}\cdot42\cdot1=840\ (J) . Answer

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