Question

A 500. gram cart moving at .360 m/s, what is its momentum?

If the cart was to bounce off a wall and return with a velocity of -.240 m/s, what is its Impulse be?  

Answer 1

(a)

$$p=mv=0.5\ kg\cdot0.36\ \dfrac{m}{s}=0.18\ kgm/s.$$

(b)

$$J=\Delta p=m(v_f-v_i),$$ $$J=0.5\ kg\cdot(-0.24\ \dfrac{m}{s}-0.36\ \dfrac{m}{s})=-0.3\ kgm/s.$$