Question #188987

Find the resultant if the following forces acts on a body


12N along x-axis

8N along y-axis

4N at 30° along x-axis


1
Expert's answer
2021-05-04T12:07:49-0400

Find the components:


F1x=12 N,F1y=0,F2x=0,F2y=8 N,F3x=4cos30°=3.46 N,F3y=4sin30°=2 N.F_{1x}=12\text{ N},\\ F_{1y}=0,\\ F_{2x}=0,\\ F_{2y}=8\text{ N},\\ F_{3x}=4\cos30°=3.46\text{ N},\\ F_{3y}=4\sin30°=2\text{ N}.\\

The resultant:


Rx=F1x+F2x+F3x=15.46 N,Ry=F1y+F2y+F3y=10 N,R=Rx2+Ry2=18.41 N, θR=arctanRyRx=32.9°.R_x=F_{1x}+F_{2x}+F_{3x}=15.46\text{ N},\\ R_y=F_{1y}+F_{2y}+F_{3y}=10\text{ N},\\ R=\sqrt{R_x^2+R_y^2}=18.41\text{ N},\\\space\\ \theta_R=\arctan\frac{R_y}{R_x}=32.9°.


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