Question #188685

what is the temperature coefficient of resistance of a piece of wire having a resistance of 12. 85 ohm at 30 degrees celsius and 6.85 ohm at 0 degrees celcius. what will be its resistance at 50 degrees celsius.


1
Expert's answer
2021-05-04T12:08:38-0400

ρ=ρ0(1+αt)\rho=\rho_0(1+\alpha t)


12.85=ρ0(1+α30)12.85=\rho_0(1+\alpha \cdot30)


6.85=ρ0(1+α0)ρ0=6.85 (Ω)6.85=\rho_0(1+\alpha \cdot0)\to\rho_0=6.85\ (\Omega) . So, we have


α=(12.85/6.851)/30=0.0292 (1/°C)\alpha=(12.85/6.85-1)/30=0.0292\ (1/°C) . Answer


ρ50=6.85(1+0.029250)=16.85 (Ω)\rho_{50}=6.85(1+0.0292\cdot50)=16.85\ (\Omega) . Answer








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