what is the temperature coefficient of resistance of a piece of wire having a resistance of 12. 85 ohm at 30 degrees celsius and 6.85 ohm at 0 degrees celcius. what will be its resistance at 50 degrees celsius.
"\\rho=\\rho_0(1+\\alpha t)"
"12.85=\\rho_0(1+\\alpha \\cdot30)"
"6.85=\\rho_0(1+\\alpha \\cdot0)\\to\\rho_0=6.85\\ (\\Omega)" . So, we have
"\\alpha=(12.85\/6.85-1)\/30=0.0292\\ (1\/\u00b0C)" . Answer
"\\rho_{50}=6.85(1+0.0292\\cdot50)=16.85\\ (\\Omega)" . Answer
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