Question

1)    A car accelerates from 2.0 m/s to speed of 10.0 m/s in 4.0 sec. If the rate of acceleration is constant, determine:

a)    Acceleration

b)    Distance traveled

Answer 1

The acceleration is the rate of change of speed:

$$a=\frac{v_f-v_i}{t}=\frac{10-2}{4}=2\text{ m/s}^2.$$

The distance traveled is

$$d=\frac{v_f^2-v_i^2}{2a}=24\text{ m}.$$