Answer to Question #185863 in Physics for christian espiritu

Question

 A satellite orbits Earth 1,250,000 m above the Earth’s surface. What is the satellite’s orbital speed? 

Answer 1

$$v=\sqrt{\frac{GM}{r}}\\v=\sqrt{\frac{(6.67\cdot10^{-11})(5.97\cdot10^{24})}{1250000+6.59\cdot10^{6}}}=7130\frac{m}{s}$$