Answer to Question #185863 in Physics for christian espiritu

Question #185863

A satellite orbits Earth 1,250,000 m above the Earth’s surface. What is the satellite’s orbital speed?

Expert's answer

"v=\\sqrt{\\frac{GM}{r}}\\\\v=\\sqrt{\\frac{(6.67\\cdot10^{-11})(5.97\\cdot10^{24})}{1250000+6.59\\cdot10^{6}}}=7130\\frac{m}{s}"

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