Answer to Question #185469 in Physics for Rj sibal

Question

What's is the magnetic field at the center of the coil of radius 5×10^-2 m carrying a current of 0. 25 A and having 40 turns

Answer 1

$$B=\frac{\mu_0NI}{2R}\\B=\frac{(40)(0.25)(4\pi\cdot10^{-7})}{2(0.05)}=1.26\cdot10^{-4}\ T$$