Answer to Question #185469 in Physics for Rj sibal

Question #185469

What's is the magnetic field at the center of the coil of radius 5×10^-2 m carrying a current of 0. 25 A and having 40 turns

Expert's answer

"B=\\frac{\\mu_0NI}{2R}\\\\B=\\frac{(40)(0.25)(4\\pi\\cdot10^{-7})}{2(0.05)}=1.26\\cdot10^{-4}\\ T"

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