Question #185458

3/8 of light initial intensity is absorbed in the beaker with length of 2cm filled with 9% solution. Find the length of beaker that should be used to get transmittance 1/3 for the same solution.


1
Expert's answer
2021-04-26T17:13:50-0400

According to Beer-Lambert law for both cases:


I1I0=ekl1=38I2I0=ekl2=18ekl2e0.02=98l2=13.7 cm\frac{I_1}{I_0}=e^{-kl_1}=\frac{3}{8}\\\frac{I_2}{I_0}=e^{-kl_2}=\frac{1}{8}\\\frac{e^{kl_2}}{e^{0.02}}=\frac{9}{8}\\l_2=13.7\ cm


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS