Answer to Question #184913 in Physics for beza

Question #184913

a 2000 kg car is being pulled up a 37 deg incline at a constant speed by a cable parallel to the incline. if the friction force is 800N WHAT IS THE WORK done by the cable on the car

Expert's answer

"W=mgh+F_fs\\\\W=(2000)(9.8)(8)\\sin{37}+800(8)\\\\=10^5\\ J=100\\ kJ"

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