Question

a research Vand de Graad enerator has 2.50mm diameter sphere with a charge of 6.00$uC$ on it.

A. what id the potential near its surface

b. at what distance from its center is potential 1.50M

Answer 1

A. Find the potential near the surface:

$$V_A=\frac{kq}{r}=43\text{ MV}.$$

B. The potential is 1.5 MV at the distance of

$$r=\frac{kq}{V_B}=3.6\text{ cm}.$$