Question

Two 80-Ω resistors are connected in series with 0.15 A flowing through them? Find

(a.) Total Resistance (Rtotal)

(b.) Voltage drop (Vt) across resistors

(c.) Current through the circuit

Answer 1

1) Total resistance for resistors, connected in series is the sum of the resistances. Hence, $R = 80 \Omega + 80 \Omega = 160 \Omega$.

2) From Ohm's law, $U = I R = 0.15 A \cdot 160 \Omega = 24 V$.

3) Current through the circuit is $0.15 A$.