The following amount of electrons is contained in the mass of m=100kg:
N=mem where me=9.11×10−31kg is the mass of one electron. The charge that is carried by this number of electrons is given as follows:
q=Ne=meme where e=−1.6×10−19C is the charge of one electron. Thus, obtain:
q=9.11×10−31100⋅(−1.6×10−19)≈−1.76×1013C Answer. −1.76×1013C.
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